2[3-(9-5r)]-r=-18+3(2+3r)

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Solution for 2[3-(9-5r)]-r=-18+3(2+3r) equation:


Simplifying
2[3 + -1(9 + -5r)] + -1r = -18 + 3(2 + 3r)
2[3 + (9 * -1 + -5r * -1)] + -1r = -18 + 3(2 + 3r)
2[3 + (-9 + 5r)] + -1r = -18 + 3(2 + 3r)

Combine like terms: 3 + -9 = -6
2[-6 + 5r] + -1r = -18 + 3(2 + 3r)
[-6 * 2 + 5r * 2] + -1r = -18 + 3(2 + 3r)
[-12 + 10r] + -1r = -18 + 3(2 + 3r)

Combine like terms: 10r + -1r = 9r
-12 + 9r = -18 + 3(2 + 3r)
-12 + 9r = -18 + (2 * 3 + 3r * 3)
-12 + 9r = -18 + (6 + 9r)

Combine like terms: -18 + 6 = -12
-12 + 9r = -12 + 9r

Add '12' to each side of the equation.
-12 + 12 + 9r = -12 + 12 + 9r

Combine like terms: -12 + 12 = 0
0 + 9r = -12 + 12 + 9r
9r = -12 + 12 + 9r

Combine like terms: -12 + 12 = 0
9r = 0 + 9r
9r = 9r

Add '-9r' to each side of the equation.
9r + -9r = 9r + -9r

Combine like terms: 9r + -9r = 0
0 = 9r + -9r

Combine like terms: 9r + -9r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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